Tìm các số nguyên x sao cho:
a) \(\frac{{ - 2}}{5} < \frac{x}{{15}} < \frac{1}{6}\)
b) \(\frac{1}{2} + \frac{1}{3} - \frac{5}{{12}} < 2x < \frac{{ - 12}}{{31}} + \frac{{ - 136}}{{ - 31}}\)
Đưa các phân số về cùng một mẫu dương rồi so sánh tử số
a)
Advertisements (Quảng cáo)
Ta có:
\(\begin{array}{l}\frac{{ - 2}}{5} = \frac{{ - 2.18}}{{5.18}} = \frac{{ - 36}}{{90}}\\\frac{x}{{15}} = \frac{{x.6}}{{15.6}} = \frac{{6x}}{{90}}\\\frac{1}{6} = \frac{{1.15}}{{6.15}} = \frac{{15}}{{90}}\end{array}\)
Do đó:
\(\begin{array}{l}\frac{{ - 2}}{5} < \frac{x}{{15}} < \frac{1}{6} \Leftrightarrow \frac{{ - 36}}{{90}} < \frac{{6x}}{{90}} < \frac{{15}}{{90}}\\ \Rightarrow - 36 < 6x < 15 \Rightarrow - 6 < x < 2,5\\ \Rightarrow x = \left\{ { - 5; - 4; - 3; - 2; - 1;0;1;2} \right\}\end{array}\)
b) Ta có:
\(\begin{array}{l}\frac{1}{2} + \frac{1}{3} - \frac{5}{{12}} = \frac{{1.6}}{{2.6}} + \frac{{1.4}}{{3.4}} - \frac{5}{{12}} = \frac{6}{{12}} + \frac{4}{{12}} - \frac{5}{{12}} = \frac{{6 + 4 - 5}}{{12}} = \frac{5}{{12}}\\\frac{{ - 12}}{{31}} + \frac{{ - 136}}{{ - 31}} = \frac{{ - 12}}{{31}} + \frac{{136}}{{31}} = \frac{{ - 12 + 136}}{{31}} = \frac{{124}}{{31}} = 4\end{array}\)
Do đó:
\(\begin{array}{l}\frac{1}{2} + \frac{1}{3} - \frac{5}{{12}} < 2x < \frac{{ - 12}}{{31}} + \frac{{ - 136}}{{ - 31}}\\ \Leftrightarrow \frac{5}{{12}} < 2x < 4 \Leftrightarrow \frac{5}{{24}} < x < 2\\ \Leftrightarrow x = 1\end{array}\)