Tìm số tự nhiên \(x\) thoả mãn:
a) (13\(x\) – 122): 5 = 5;
b) 3\(x\)[82 - 2.(25 - 1)] = 2022.
+) \(x:a=b \Rightarrow x=b.a\)
+) \(x.a=b \Rightarrow x=b:a\)
+) \(x-a=b \Rightarrow x=b+a\)
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a)
\(\begin{array}{l}\left( {13x{\rm{ }}-{\rm{ }}{{12}^2}} \right):{\rm{ }}5{\rm{ }} = {\rm{ }}5\\13x{\rm{ }}-{\rm{ }}{12^2} = 5.5\\13x{\rm{ }}-{\rm{ }}144 = 25\\13x = 25 + 144\\13x = 169\\x = 13\end{array}\)
Vậy \(x = 13\)
b)
\(\begin{array}{l}3x\left[ {{8^2} - 2.\left( {{2^5} - {\rm{ }}1} \right)} \right]{\rm{ }} = {\rm{ }}2022\\3x\left[ {64 - 2.\left( {32 - {\rm{ }}1} \right)} \right]{\rm{ }} = {\rm{ }}2022\\3x\left[ {64 - 2.31} \right]{\rm{ }} = {\rm{ }}2022\\3x\left( {64 - 62} \right){\rm{ }} = {\rm{ }}2022\\3x.2 = 2022\\6x = 2022\\x = 337\end{array}\)
Vậy \(x = 337.\)