Câu hỏi 1 trang 68 Hóa 12 Kết nối tri thức: Viết bán phản ứng hoặc cặp oxi hoá – khử còn thiếu trong bảng dưới đây vào vở...

Bán phản ứng

Cặp oxi hóa – khử

Bán phản ứng

Cặp oxi hóa – khử

${\rm{N}}{{\rm{a}}^{\rm{ + }}} + 1{\rm{e}} \mathbin{\lower.3ex\hbox{$\buildrel\textstyle\rightarrow\over{\smash{\leftarrow}\vphantom{_{\vbox to.5ex{\vss}}}}$}} {\rm{Na}}$

?

?

${\rm{2}}{{\rm{H}}^{\rm{ + }}}{\rm{/}}{{\rm{H}}_{\rm{2}}}$

?

${\rm{A}}{{\rm{l}}^{{\rm{3 + }}}}{\rm{/Al}}$

${\rm{A}}{{\rm{g}}^{\rm{ + }}} + 1{\rm{e}} \mathbin{\lower.3ex\hbox{$\buildrel\textstyle\rightarrow\over{\smash{\leftarrow}\vphantom{_{\vbox to.5ex{\vss}}}}$}} {\rm{Ag}}$

?

${\rm{F}}{{\rm{e}}^{{\rm{2 + }}}} + 2{\rm{e}} \mathbin{\lower.3ex\hbox{$\buildrel\textstyle\rightarrow\over{\smash{\leftarrow}\vphantom{_{\vbox to.5ex{\vss}}}}$}} {\rm{Fe}}$

?

?

${\rm{A}}{{\rm{u}}^{{\rm{3 + }}}}{\rm{/Au}}$

Bán phản ứng

Cặp oxi hóa – khử

Bán phản ứng

Cặp oxi hóa – khử

${\rm{N}}{{\rm{a}}^{\rm{ + }}} + 1{\rm{e}} \mathbin{\lower.3ex\hbox{$\buildrel\textstyle\rightarrow\over{\smash{\leftarrow}\vphantom{_{\vbox to.5ex{\vss}}}}$}} {\rm{Na}}$

Na⁺/Na

${\rm{2}}{{\rm{H}}^{\rm{ + }}} + 2{\rm{e}} \mathbin{\lower.3ex\hbox{$\buildrel\textstyle\rightarrow\over{\smash{\leftarrow}\vphantom{_{\vbox to.5ex{\vss}}}}$}} {{\rm{H}}_2}$

${\rm{2}}{{\rm{H}}^{\rm{ + }}}{\rm{/}}{{\rm{H}}_{\rm{2}}}$

${\rm{A}}{{\rm{l}}^{{\rm{3 + }}}} + 3{\rm{e}} \mathbin{\lower.3ex\hbox{$\buildrel\textstyle\rightarrow\over{\smash{\leftarrow}\vphantom{_{\vbox to.5ex{\vss}}}}$}} {\rm{Al}}$

${\rm{A}}{{\rm{l}}^{{\rm{3 + }}}}{\rm{/Al}}$

${\rm{A}}{{\rm{g}}^{\rm{ + }}} + 1{\rm{e}} \mathbin{\lower.3ex\hbox{$\buildrel\textstyle\rightarrow\over{\smash{\leftarrow}\vphantom{_{\vbox to.5ex{\vss}}}}$}} {\rm{Ag}}$

Ag⁺/Ag

${\rm{F}}{{\rm{e}}^{{\rm{2 + }}}} + 2{\rm{e}} \mathbin{\lower.3ex\hbox{$\buildrel\textstyle\rightarrow\over{\smash{\leftarrow}\vphantom{_{\vbox to.5ex{\vss}}}}$}} {\rm{Fe}}$

Fe²⁺/Fe

${\rm{A}}{{\rm{u}}^{{\rm{3 + }}}} + 3{\rm{e}} \mathbin{\lower.3ex\hbox{$\buildrel\textstyle\rightarrow\over{\smash{\leftarrow}\vphantom{_{\vbox to.5ex{\vss}}}}$}} {\rm{Au}}$

${\rm{A}}{{\rm{u}}^{{\rm{3 + }}}}{\rm{/Au}}$