Tính: a) 889972 + 96308;. Bài 1 trang 158 sgk toán 5 - Phép cộng
Tính:
a) 889972 + 96308;
b) \(\frac{5}{6}\) + \(\frac{7}{12}\) ;
c) 3 + \(\frac{5}{7}\) ;
d) 926,83 + 549,67 ;
a) 889972 + 96308 = 986280 ;
b) \(\frac{5}{6}\) + \(\frac{7}{12}\) = \(\frac{10}{12}\) + \(\frac{7}{12}\) = \(\frac{17}{12}\) ;
c) 3 + \(\frac{5}{7}\) = \(\frac{21}{7}\) + \(\frac{5}{7}\) = \(\frac{26}{7}\) (hoặc 3 + \(\frac{5}{7}\) = \(3\frac{5}{7}\) ) ;
d) 926,83 + 549,67 = 1476,5 ;