Tính nhanh:
\(\eqalign{& B = {{ – 2} \over {17}} + {{15} \over {23}} + {{ – 15} \over {17}} + {4 \over {19}} + {8 \over {23}} \cr & C = {{ – 1} \over 2} + {3 \over {21}} + {{ – 2} \over 6} + {{ – 5} \over {30}} \cr} \)
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\(\eqalign{& B = {{ – 2} \over {17}} + {{15} \over {23}} + {{ – 15} \over {17}} + {4 \over {19}} + {8 \over {23}} \cr & = \left( {{{ – 2} \over {17}} + {{ – 15} \over {17}}} \right) + \left( {{{15} \over {23}} + {8 \over {23}}} \right) + {4 \over {19}} \cr & = \left( {{{ – 2 + ( – 15)} \over {17}}} \right) + \left( {{{15 + 18} \over {23}}} \right) + {4 \over {19}} \cr & = \left( {{{ – 17} \over 7}} \right) + \left( {{{23} \over {23}}} \right) + {4 \over 9} \cr & = \left( { – 1} \right) + 1 + {4 \over 9} = 0 + {4 \over {19}} = {4 \over {19}} \cr & C = {{ – 1} \over 2} + {3 \over {21}} + {{ – 2} \over 6} + {{ – 5} \over {30}} \cr & = {{ – 1} \over 2} + {1 \over 7} + {{ – 2} \over 6} + {{ – 1} \over 6} \cr & = {{ – 1} \over 2} + {1 \over 7} + \left( {{{ – 2} \over 6} + {{ – 1} \over 6}} \right) \cr & = {{ – 1} \over 2} + {1 \over 7} + {{ – 3} \over 6} \cr & = {{ – 1} \over 2} + {1 \over 7} + {{ – 1} \over 2} \cr & = \left( {{{ – 1} \over 2} + {{ – 1} \over 2}} \right) + {1 \over 7} \cr & = {{ – 2} \over 2} + {1 \over 7} \cr & = – 1 + {1 \over 7} = {{ – 7} \over 7} + {1 \over 7} \cr & = {{ – 7 + 1} \over 7} = {{ – 6} \over 7} \cr} \)