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Bài 64. Làm tính chia:
a) \(( – 2{x^5} + 3{x^2} – 4{x^3}):2{x^2}\);
b) \(({x^3} – 2{x^2}y + 3x{y^2}):\left( { – {1 \over 2}x} \right)\);
c) \((3{x^2}{y^2} + 6{x^2}{y^3} – 12xy):3xy\).
a) \(( – 2{x^5} + 3{x^2} – 4{x^3}):2{x^2} \)
\(= – {2 \over 2}{x^{5 – 2}} + {3 \over 2}{x^{2 – 2}} – {4 \over 2}{x^{3 – 2}} = – {x^3} + {3 \over 2} – 2x\)
b) \(({x^3} – 2{x^2}y + 3x{y^2}):\left( { – {1 \over 2}x} \right) \)
\(= \left( {{x^3}:\left( { – {1 \over 2}x} \right)} \right) + \left( { – 2{x^2}y:\left( { – {1 \over 2}x} \right)} \right) + \left( {3x{y^2}:\left( { – {1 \over 2}x} \right)} \right)\)
\(= – 2{x^2} + 4xy – 6{y^2}\)
c) \((3{x^2}{y^2} + 6{x^2}{y^3} – 12xy):3xy\)
\(=(3{x^2}{y^2}:3xy) + (6{x^2}{y^3}:3xy) + ( – 12xy:3xy) \)
\(= xy + 2x{y^2} – 4\)