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Bài 37 Tìm giá trị của biểu thức sau
a) \(\frac{4^{2}.4^{3}}{2^{10}}\)
b) \(\frac{(0,6)^{5}}{(0,2)^{6}}\)
c)\(\frac{2^{7}. 9^{3}}{6^{5}.8^{2}}\)
d) \(\frac{6^{3} + 3.6^{2}+ 3^{3}}{-13}\)
Advertisements (Quảng cáo)
a) \(\frac{4^{2}.4^{3}}{2^{10}}\) = \(\frac{4^{5}}{(2^{2})^{5}}=\frac{4^{5}}{4^{5}}= 1\)
b) \(\frac{(0,6)^{5}}{(0,2)^{6}}\) = \(\frac{(0,2.5)^{5}}{(0,2)^{6}} = \frac{(0,2)^{5}.3^{5}}{(0,2)^{5}.0,2} = \frac{3^{5}}{0,2} = \frac{243}{0,2}= 1215\)
c) \(\frac{2^{7}. 9^{3}}{6^{5}.8^{2}}\) = \(-1\)
d) \(\frac{6^{3} + 3.6^{2}+ 3^{3}}{-13}\) = \(\frac{2^{3}.3^{3} + 3^{2}.2^{2} + 3^{3}}{-13} = \frac{3^{3}.(2^{3} + 2^{2} + 1)}{-13} = -3^{3} = -27\)