Tìm x, biết :
a) \({3 \over 5}.x + {1 \over 5} = {4 \over 5}\)
b) \({5 \over 3}.x - {7 \over 6} = {{11} \over 2}\).
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\(\eqalign{ & a){3 \over 5}x + {1 \over 5} = {4 \over 5} \cr & {3 \over 5}x = {4 \over 5} - {1 \over 5} \cr & {3 \over 5}x = {3 \over 5} \cr & x = {3 \over 5}:{3 \over 5} \Leftrightarrow x = 1 \cr & b){5 \over 3}x - {7 \over 6} = {{11} \over 2} \cr & {5 \over 3}x = {{11} \over 2} + {7 \over 6} \cr & {5 \over 3}x = {{33} \over 6} + {7 \over 6} \cr & {5 \over 3}x = {{20} \over 3} \cr & x = {{20} \over 3}:{5 \over 3} \cr & x = {{20} \over 5}.{3 \over 5} \Leftrightarrow x = 4. \cr} \)