Làm tính chia:
a. \(\left( {5{x^4} - 3{x^3} + {x^2}} \right):3{x^2}\)
b. \(\left( {5x{y^2} + 9xy - {x^2}{y^2}} \right):\left( { - xy} \right)\)
c. \(\left( {{x^3}{y^3} - {1 \over 2}{x^2}{y^3} - {x^3}{y^2}} \right):{1 \over 3}{x^2}{y^2}\)
a. \(\left( {5{x^4} - 3{x^3} + {x^2}} \right):3{x^2}\)
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\( = \left( {5{x^4}:3{x^2}} \right) + \left( { - 3{x^3}:3{x^2}} \right) + \left( {{x^2}:3{x^2}} \right) = {5 \over 3}{x^2} - x + {1 \over 3}\)
b. \(\left( {5x{y^2} + 9xy - {x^2}{y^2}} \right):\left( { - xy} \right)\)
\( = \left[ {5x{y^2}:\left( { - xy} \right)} \right] + \left[ {9xy:\left( { - xy} \right)} \right] + \left[ {\left( { - {x^2}{y^2}} \right):\left( { - xy} \right)} \right] = - 5y - 9 + xy\)
c. \(\left( {{x^3}{y^3} - {1 \over 2}{x^2}{y^3} - {x^3}{y^2}} \right):{1 \over 3}{x^2}{y^2}\)
\(\eqalign{& = \left( {{x^3}{y^3}:{1 \over 3}{x^2}{y^2}} \right) + \left( { - {1 \over 2}{x^2}{y^3}:{1 \over 3}{x^2}{y^2}} \right) + \left( { - {x^3}{y^2}:{1 \over 3}{x^2}{y^2}} \right) \cr & = 3xy - {3 \over 2}y - 3x \cr} \)