Tính:
\(\eqalign{ & a)\,\,A = {{ - 2} \over 5} + \left( { - {2 \over 3}} \right) - \left( {{1 \over 2}} \right) \cr & b)\,\,B = \left( { - {3 \over 9}} \right).{3 \over {11}} - {6 \over 9}.{3 \over {11}} \cr} \)
Advertisements (Quảng cáo)
\(\eqalign{ & a)A = {{ - 2} \over 5} + \left( { - {2 \over 5}} \right) - \left( {{1 \over 2}} \right) = {{ - 24} \over {60}} - {{40} \over {60}} - {{30} \over {60}} = {{ - 94} \over {60}} = - 1{{17} \over {30}} \cr & b)B = \left( { - {3 \over 9}} \right).{3 \over {11}} - {6 \over 9}.{3 \over {11}} = {3 \over {11}}.\left( { - {3 \over 9} - {6 \over 9}} \right) = {3 \over {11}}.( - 1) = {{ - 3} \over {11}} \cr} \)